Re: [LI] Help required on Linux

["Archan Paul" <archanp@xxxxxxxxxxx>]

h hi !!! An intuitive answer Raj.

Archan
archanp@xxxxxxxxxxx

----- Original Message ----- 
From: Raj Mathur <raju@xxxxxxx>
To: <linux-india@xxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, November 09, 1999 10:01 AM
Subject: Re: [LI] Help required on Linux 


> I'd suggest:
> 
> 1.  Search the web a bit before posting.  All the information you need 
> is available online at 1000's of sites, so there's really no need to
> repeat the same questions on the mailing list.  In fact, a lot of this 
> information is already available on your Linux computer itself.
> 
> 2.  Get a good consultant to help you setup your services.  I don't
> want to be rude, but unless you learn to help yourself a bit you will
> never be able to do anything useful with Linux.  And spoonfeeding of
> the sort you're looking for just doesn't exist in the Linux universe,
> except by paid consultants, so you may as well get one of those and
> help feed his/her poor babies (or support his mistress in the style to 
> which she's accustomed, or help him pay off the loan on his S-class
> Mercedes, or whatever :-) .
> 
> -- Raju
> 
> >>>>> "Akshara" == Akshara Technologies <girish@xxxxxxxxxxxxxxx> writes:
> 
>     Akshara> Anand, Thanks for your reply. Can you tell me what PHP3
>     Akshara> is and where I can get it?
> 
>     >> 99% of the software required by you are free of cost (except
>     >> for the ASP plugin) why not use PHP3 it's free and better
> 
>     Akshara> TIA, Girish
> --------------------------------------------------------------------
> The Linux India Mailing List Archives are now available.  Please search
> the archive at http://lists.linux-india.org/ before posting your question
> to avoid repetition and save bandwidth.
> 

--------------------------------------------------------------------
The Linux India Mailing List Archives are now available.  Please search
the archive at http://lists.linux-india.org/ before posting your question
to avoid repetition and save bandwidth.