to remove the loging prompt and password...............

[john slater <johnslater2000@xxxxxxxxx>]

hello
     i am in to development of a linux thin Client,
insteated of a bootrom i am using a M-System
diskonchip, i am in the inital stages of development,
the diskonchip contains the base os(Red Hat 6.0),
X-drivers, network drives,... etc with all other
services, the status of the project is that the linux
has recognized the diskonchip, i have put all the
neccessary files to boot, even the lilo is updated, 
the problem is that i am not abel to remove the login
prompt, which is not required in the project,
     i will be pleased if some one can help me in
removing the login prompt and password,
thank u
Syed Mudasir Ahmed

--- Arvind Devarajan <arvind.sankruthi@xxxxxxxxxx>
wrote:
> hi vibhu,
>     correct. you cannot connect to networks between
> which there are firewalls.
> for example, you know that www.redhat.com is at
> 216.148.218.195, still you
> cannot connect to it only because you will have
> firewalls both in your side
> (your company firewall) and at redhat.
>     firewalls basically would look at your IP
> packets. they would extract
> source address, and have certain policies depending
> upon the destination
> addresses. for example, your firewall might have
> been configured so that all
> packets having a destination address, the network
> part of which is not any
> local network should be dropped. an example with
> numbers: suppose your network
> is 192.168.20.0, you might have a firewall installed
> at the gate way that
> drops all packets whose destination address is for
> networks other than
> 192.168.20.0. This effectively blocks you from
> accessing other networks.
>     similarly, firewall could be configured so that
> they accept only packets
> whose source address is some trustable network - for
> example, "accept all
> packets from network 192.168.30.0, 192.168.25.0,
> etc." When this configuration
> exists, all packets belonging to networks not in the
> above list are dropped.
>     what you can understand from this is: while you
> use the socket API to send
> and receive packets, your OS network software
> constructs IP packets with
> source and destination address specified by you (in
> the simplest case). and,
> this is not in your control - assuming that you are
> not using RAW sockets.
> finally, the firewalls look into these IP packets,
> and filter your packets....
> and, might not allow you to connect to certain
> systems.
> 
> arvind.
> 
> Vibhu Rishi wrote:
> 
> > Correct me if I am worng ..
> >
> > your IP address is something like  192.191.70.90
> and you want to connect to
> > 192.191.80.90 ?
> >
> > no problem if you are in the same network - no
> firewalls in between.
> >
> > if you have a firewall/proxy server in between,
> then I don't know. - any
> > one out there who knows how this can be done ?
> >
> > vibhu..
> >
> > Ramesh wrote:
> >
> > > hi all,
> > >
> > > i want to communicate to a machine in different
> subnet means how to
> > > acheive it with socket porgramming... i did the
> same thing lihke
> > > creatinga socket and establishing a connection
> with a machine with the
> > > local subnet ... but when i wawnt to connect to
> a valid ip machine or a
> > > machine in diffrent subnet.. how to acheive it
> programmatically.... can
> > > anybody help me...
> > >
> > > ramesh
> > >
> > >
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> >
>
..........................................................................
> > To know the road ahead, ask those coming back.
> -Chinese Proverb
> >
>
--------------------------------------------------------------------------
> > Vibhu Rishi             e@   vibhu.rishi@xxxxxxxxx
> > Sr. Systems Engineer    ring@  
> 8520408/416/419/420/424/425
> > WIPRO    ext.: 2109
> > Electronic City  - Bangalore
> >
>
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> >
> > ---------------------------------------------
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> > for a purpose.  Violations of the rules of
> > this list will result in stern action.
> 
> 
> ---------------------------------------------
> LIP is all for free speech.  But it was created
> for a purpose.  Violations of the rules of
> this list will result in stern action.


=====
John Slater
#123, Hooly Wood
LA, CA 34523

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