Re: i = i++

[sindhoor pangal <sindhoor@xxxxxxxxx>]

 the C standard says, in section
> 6.5,
> 
>        [#2] Between the previous and next sequence
> point an  object
>        shall  have  its  stored  value modified at
> most once by the
>        evaluation of an expression.  Furthermore,
> the  prior  value
>        shall  be  accessed  only  to  determine  the
>  value  to  be
>        stored.60)                                   
>                *


ok! so does this mean that even a statement like 
	++i++ ;
is not defined. i thought that prefix has precedence
over postfix . so the statement evaluates to (++i)++.
since prefix returns an lvalue, it can be operated on
by postfix and so it sould give a difinite answer. am
i wrong ?

btw. i asked this question coz we were asked a
question like i = i+++++i+i++ ; in some apptitude test
and the people who evaluated claimed that the answer
'undefined' was wrong! beat that!

> 
> And the footnote 60 is:
> 
>        60)This paragraph renders  undefined 
> statement  expressions
>           such as
>                   i = ++i + 1;
>                   a[i++] = i;
>           while allowing
>                   i = i + 1;
>                   a[i] = i;
> 
> The standard is quite clear here that the original
> expression (i = i++;)
> is undefined.
> 
> Binand
> 
> 
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