Re: function arguments

["Mahesh" <maheshv@xxxxxxxxxxxx>]

Hi deepak,

  you can try the implementation of printf for your problem
here is a sample program which shows you the variable argument
implementation
forgive me for my bad programming style but here it is anyway...
this is just an excert from my sample programs i had written when i was a
stiudent

void main( void )
{
 int y,p,q,r,s,t;
 printf( "Average is: %d\n", average(10,y,p,q,r,s,t) );
}
/*
int average(int cc,int first ... )
{
   cout << cc << endl;
   int count = 0, sum = 0;
   void *i ;
   va_list marker;
   va_start( marker, first );
//   intvec.push_back(&first);
   i = new int(10);

   while( first > 0 )


      count++;
      *(int *)i = (int)va_arg( marker, int);
       int *x = new int;
       *x  = *(int *)i;

      intvec.push_back(x);
      ( first)--;
   }
   va_end( marker );

   for(count=0,iter = intvec.begin(); iter!= intvec.end() ; iter++)
    cout << (*(int *)(*iter)) << endl;

   return 1;
}


regards
mahesh
- mahesh@xxxxxxx


----- Original Message -----
From: deepak yadav <deepak2000@xxxxxxxxxxxx>
To: linux-india-programmers <linux-india-programmers@xxxxxxxxxxxxxxxxxxxxx>
Sent: Friday, June 30, 2000 11:22 AM
Subject: [LIP] function arguments


> hi
> i posted this problem earlier but i am not receiving any mails from LIP.
please help me out.
>
> i have to print some values. i don't know before hand what is their type
and number which can only be determined when it is run.
> i want to do something like
>
> for(i = 0; i < num ; i++ ) {
>    str = getFormatSpecifierString(i);
>    printf(str, value[i]);
> }
>
> is such thing possible. what kind of array 'value' be.
>
> thanks
>
> -----------------------------
> reply soon
> bye
>
>  __ deepak __
>
> have a great day
> ICQ 30662394
> -
> -
>
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>
>
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