RE: i = i++

["Kondaiah (IE10)" <Kondaiah@xxxxxxxxxxxxx>]

Hi,
In the case of C++  you are determinign in the postincrement
	temp=num;
	num=num+1;
	return temp;
when u return this we will have old value in temp  we will have and
incremented value in num=2;
after that we are doing assignment num=temp(uisng operator =) now num
contains 1.

where as in the case of c it just an increment(Mind the result depending the
compiler in this case).

This is indicating that by using operator overloading we can solve this kind
of problems.
Thanks,
Kondaiah Dasari 
	

> -----Original Message-----
> From:	sindhoor pangal [SMTP:sindhoor@xxxxxxxxx]
> Sent:	Wednesday, January 10, 2001 6:53 PM
> To:	LIP
> Subject:	[LIP] i = i++
> 
> hi
> what should the outcome of this program be ?
> 
> void main()
> {
>     int i = 1 ;
>     i = i++ ;
>     cout<<i ;
> }
> 
> i got the oputput as 2. but the following program gave
> me 1
> 
> class A
> {
>     int num ;
>     public :
> 	A(int n) : num(n) {}
> 	A & operator = (const A & rhs)
> 	{num = rhs.num ; return *this ;}	
> 	A operator ++(int)
> 	{A temp(num) ; num = num + 1 ; return temp ;}
> 	operator int()
> 	{return num ;}
> } ;
> 
> void main()
> {
>     A a(1) ;
>     a = a++ ;
>     cout<<a ;
> }
> 
> the result is the same on g++ and vc. i dont
> understand. please help.
> sindhoor
> 
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