Re: C Program

[sojan@xxxxxxxxxxxxxxxx]

Wow!...this is interesting. Here is a gdb session on the file..

(gdb) break 10
Breakpoint 1 at 0x80483df: file tt.c, line 10.
(gdb) r
Starting program: /home10/sojan/./a.out 

Breakpoint 1, main () at tt.c:10
10                  printf("\n%x",add);
(gdb) p add
$1 = {int (int, int)} 0x80483c8 <add>
(gdb) p *add
$2 = {int (int, int)} 0x80483c8 <add>
(gdb) p *(*add)
$3 = {int (int, int)} 0x80483c8 <add>
(gdb) p add(2,3)

 I am there 
$4 = 14
(gdb) 


Is this in some way related to the fact that we need not dereference a
pointer to a function to call it?....but it still doesn't make sense, does
it?




On Thu, 12 Oct 2000, Rajani K wrote:

> Hi All!!
> 
> heres a piece of C code,
> 
> #include<stdio.h>
> 
> int add(int a, int b)
> {
>     printf ( "\n I am there \n" );
> }
> 
> main()
> {
>     printf("\n%x",add);
>     printf("\n%x",*add);
>     printf("\n%x",*(*(*(*add))));
> }
> 
> The Compiler does not crib. The program gets built and
> the result prints the same value for all the above three printfs.
> What can be the probable reason ?
> 
> TIA!!
> 
> Cheers
> Rajani
> 
> 
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-- 
Sojan James
Consultant, National Semi. India Designs Ltd.
7/6 Brunton Road, Bangalore 560025. India.
Ph: 5587918/919/920 ext. 308