Re: [LI] j = ++i * ++i * ++i

[Rohit <rohits@xxxxxxxxxxxxxx>]

> > > if i is initialized to say 3,
> > > what will be the value of j, where
> > > j = ++i * ++i * ++i;
> > > on solaris
> > > using cc answer is
> > > j = 6 * 6 * 6;
> 
> unary operators has higher priorty over binary operators.
> so all ++i will get evaluated first justifying above.
> (using only one copy of i)

And this is where I have a problem. Who forced (using only one copy of
i) ??

> > > using gcc answer is
> > > j = 4 * 5 * 6;
> 
> after each ++i, value of i at that time is stored somewhere (buffers???)
> so that while evaluating the expression appropiate value of i is chosen
> to give above answer.

And what is then this 'appropriate' ?
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