RE: [LI] j = ++i * ++i * ++i

["Urmil Parikh" <urmil@xxxxxxxxxxxx>]

| -----Original Message-----
| > > using gcc answer is
| > > j = 4 * 5 * 6;
| 
| after each ++i, value of i at that time is stored somewhere (buffers???)
| so that while evaluating the expression appropiate value of i is chosen
| to give above answer.

That buffer is the stack, isn't it?

| > > but on linux (RH6.1 PCQ)
| > > j = 5 * 5 * 6;
| > > can anybody explain logic behind j's value on linux???
| > 
| > And can you explain the logic behind the value of j anywhere else?

No answer till now

Regards
Urmil Parikh
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