RE: [LI] Catching SIGSEGV

["Ajit, Kumar (IE10)" <ajit.kumar@xxxxxxxxxxxxx>]

Hi Vimal,
	Please note that YOU ARE HANDLING THE SIGSEGV signal ON YOUR OWN so
it's your responsibility to handle the exit also, otherwise it will keep on
printing <Seg. Fault>. The action ,kernel takes when segmentation fault
occurs, is :
--> dump the core image 
--> exit the program
(off course there is one case in which we get a message
Segmentation fault occurred
without any core dump)
Since you are taking the responsibility of kernel on your shoulder so please
take care of this.
Put exit(0); in the signal handler function and you'll get <Seg. Fault> only
once.
HTH
Ajit 
----------------------------------------------------------------------------
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Best way to learn Linux is to put comments in the source code
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> -----Original Message-----
> From:	Vimal Mathew [SMTP:vml@xxxxxxxxxxxxx]
> Sent:	Monday, January 17, 2000 2:56 PM
> To:	linux-india@xxxxxxxxxxxxxxxxxxxxx
> Subject:	[LI] Catching SIGSEGV
> 
> Hi,
> 	A program I wrote used a signal handler for SIGSEGV. I originally
> compiled it without any extra flags. When any instruction in the program
> seg. faulted, it would get a large no. of Segmentation fault signals (I
> checked with strace and ltrace), and the program would exit. The same
> program, if compiled with optimization flags (-O2) would work as expected.
> I tried compiling with both gcc and egcs under RH5.2 and egcs in RH6.1.
> The program fragment is given below
> 
> jmp_buf env;
> 
> void seg_catch()
> {
> 	printf("<Seg. fault>\n");
> 	longjmp(env, 1);
> }
> main()
> {
> 	......	/* Setup handlers etc. */
> 	......
> 	if (setjmp(env) == 0) {
> 		....
> 		<seg. faulting statements>
> 	} else {
> 		....
> 	}
> }
> 
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