Re: [LI] C Programming problem

[Shourya Sarcar <sarcar@xxxxxxxx>]

Hi Mrinal,
    This is happening because initally all screen (thats a file in Unix remember
!) bound stuff is stored in a buffer.
You are experiencin the buffering effect.

Add this line
fflush(stdout);

after your printf ("Loading..");

and things should run fine.

Regards
Shourya


Mrinal Kalakrishnan wrote:

> Hi,
>
> This particular piece of code behaves differently when compiled with gcc
> (Linux), when compared to Turbo C or DJGPP (in DOS).
>
>         #include <stdio.h>
>
>         void main()
>         {
>                 printf("Loading..");
>                 float i,j;
>                 j=12345.6789;
>                 for (i=0.0;i<50000.0;i+=0.01) j=j*j;
>                 printf("Done\n");
>         }
>
> The expected behaviour would be that "Loading" gets printed, then a delay, and
> then "Done" gets printed. But, that doesn't happen. Instead, there is a long
> delay initially, then "loading" and "done" get printed immediately one after
> the other. However, if I add a newline in the "Loading" string, then it gets
> printed immediately, followed by the delay.
>
> Anybody faced this problem before - any solutions?
>
> ----------------------------------------------------------------
> Mrinal Kalakrishnan
> mrinal@xxxxxxxxx
> http://listen.to/mrinal
> ----------------------------------------------------------------
> --------------------------------------------------------------------
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--
_______________________________________________________________
Shourya Sarcar
Student
Department of Computer Science and Engineering
Jadavpur University
Calcutta, India 700 032

Email   : sarcar@xxxxxxxx
Tel     : 91-033-471 0477
Address : 364/3 Netaji Subhas Chandra Bose Road
          Calcutta , India 700 047
_______________________________________________________________





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